Optimal. Leaf size=196 \[ -\frac{8 (19 A-9 B) \tan (c+d x)}{15 a^3 d}+\frac{(13 A-6 B) \tanh ^{-1}(\sin (c+d x))}{2 a^3 d}+\frac{(13 A-6 B) \tan (c+d x) \sec (c+d x)}{2 a^3 d}-\frac{4 (19 A-9 B) \tan (c+d x) \sec (c+d x)}{15 d \left (a^3 \cos (c+d x)+a^3\right )}-\frac{(11 A-6 B) \tan (c+d x) \sec (c+d x)}{15 a d (a \cos (c+d x)+a)^2}-\frac{(A-B) \tan (c+d x) \sec (c+d x)}{5 d (a \cos (c+d x)+a)^3} \]
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Rubi [A] time = 0.541149, antiderivative size = 196, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.194, Rules used = {2978, 2748, 3768, 3770, 3767, 8} \[ -\frac{8 (19 A-9 B) \tan (c+d x)}{15 a^3 d}+\frac{(13 A-6 B) \tanh ^{-1}(\sin (c+d x))}{2 a^3 d}+\frac{(13 A-6 B) \tan (c+d x) \sec (c+d x)}{2 a^3 d}-\frac{4 (19 A-9 B) \tan (c+d x) \sec (c+d x)}{15 d \left (a^3 \cos (c+d x)+a^3\right )}-\frac{(11 A-6 B) \tan (c+d x) \sec (c+d x)}{15 a d (a \cos (c+d x)+a)^2}-\frac{(A-B) \tan (c+d x) \sec (c+d x)}{5 d (a \cos (c+d x)+a)^3} \]
Antiderivative was successfully verified.
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Rule 2978
Rule 2748
Rule 3768
Rule 3770
Rule 3767
Rule 8
Rubi steps
\begin{align*} \int \frac{(A+B \cos (c+d x)) \sec ^3(c+d x)}{(a+a \cos (c+d x))^3} \, dx &=-\frac{(A-B) \sec (c+d x) \tan (c+d x)}{5 d (a+a \cos (c+d x))^3}+\frac{\int \frac{(a (7 A-2 B)-4 a (A-B) \cos (c+d x)) \sec ^3(c+d x)}{(a+a \cos (c+d x))^2} \, dx}{5 a^2}\\ &=-\frac{(A-B) \sec (c+d x) \tan (c+d x)}{5 d (a+a \cos (c+d x))^3}-\frac{(11 A-6 B) \sec (c+d x) \tan (c+d x)}{15 a d (a+a \cos (c+d x))^2}+\frac{\int \frac{\left (a^2 (43 A-18 B)-3 a^2 (11 A-6 B) \cos (c+d x)\right ) \sec ^3(c+d x)}{a+a \cos (c+d x)} \, dx}{15 a^4}\\ &=-\frac{(A-B) \sec (c+d x) \tan (c+d x)}{5 d (a+a \cos (c+d x))^3}-\frac{(11 A-6 B) \sec (c+d x) \tan (c+d x)}{15 a d (a+a \cos (c+d x))^2}-\frac{4 (19 A-9 B) \sec (c+d x) \tan (c+d x)}{15 d \left (a^3+a^3 \cos (c+d x)\right )}+\frac{\int \left (15 a^3 (13 A-6 B)-8 a^3 (19 A-9 B) \cos (c+d x)\right ) \sec ^3(c+d x) \, dx}{15 a^6}\\ &=-\frac{(A-B) \sec (c+d x) \tan (c+d x)}{5 d (a+a \cos (c+d x))^3}-\frac{(11 A-6 B) \sec (c+d x) \tan (c+d x)}{15 a d (a+a \cos (c+d x))^2}-\frac{4 (19 A-9 B) \sec (c+d x) \tan (c+d x)}{15 d \left (a^3+a^3 \cos (c+d x)\right )}-\frac{(8 (19 A-9 B)) \int \sec ^2(c+d x) \, dx}{15 a^3}+\frac{(13 A-6 B) \int \sec ^3(c+d x) \, dx}{a^3}\\ &=\frac{(13 A-6 B) \sec (c+d x) \tan (c+d x)}{2 a^3 d}-\frac{(A-B) \sec (c+d x) \tan (c+d x)}{5 d (a+a \cos (c+d x))^3}-\frac{(11 A-6 B) \sec (c+d x) \tan (c+d x)}{15 a d (a+a \cos (c+d x))^2}-\frac{4 (19 A-9 B) \sec (c+d x) \tan (c+d x)}{15 d \left (a^3+a^3 \cos (c+d x)\right )}+\frac{(13 A-6 B) \int \sec (c+d x) \, dx}{2 a^3}+\frac{(8 (19 A-9 B)) \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{15 a^3 d}\\ &=\frac{(13 A-6 B) \tanh ^{-1}(\sin (c+d x))}{2 a^3 d}-\frac{8 (19 A-9 B) \tan (c+d x)}{15 a^3 d}+\frac{(13 A-6 B) \sec (c+d x) \tan (c+d x)}{2 a^3 d}-\frac{(A-B) \sec (c+d x) \tan (c+d x)}{5 d (a+a \cos (c+d x))^3}-\frac{(11 A-6 B) \sec (c+d x) \tan (c+d x)}{15 a d (a+a \cos (c+d x))^2}-\frac{4 (19 A-9 B) \sec (c+d x) \tan (c+d x)}{15 d \left (a^3+a^3 \cos (c+d x)\right )}\\ \end{align*}
Mathematica [B] time = 4.67301, size = 610, normalized size = 3.11 \[ -\frac{1920 (13 A-6 B) \cos ^6\left (\frac{1}{2} (c+d x)\right ) \left (\log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )-\log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )+\sec \left (\frac{c}{2}\right ) \sec (c) \cos \left (\frac{1}{2} (c+d x)\right ) \sec ^2(c+d x) \left ((870 B-1235 A) \sin \left (\frac{d x}{2}\right )+5 (761 A-366 B) \sin \left (\frac{3 d x}{2}\right )-4329 A \sin \left (c-\frac{d x}{2}\right )+1989 A \sin \left (c+\frac{d x}{2}\right )-3575 A \sin \left (2 c+\frac{d x}{2}\right )-475 A \sin \left (c+\frac{3 d x}{2}\right )+2005 A \sin \left (2 c+\frac{3 d x}{2}\right )-2275 A \sin \left (3 c+\frac{3 d x}{2}\right )+2673 A \sin \left (c+\frac{5 d x}{2}\right )+105 A \sin \left (2 c+\frac{5 d x}{2}\right )+1593 A \sin \left (3 c+\frac{5 d x}{2}\right )-975 A \sin \left (4 c+\frac{5 d x}{2}\right )+1325 A \sin \left (2 c+\frac{7 d x}{2}\right )+255 A \sin \left (3 c+\frac{7 d x}{2}\right )+875 A \sin \left (4 c+\frac{7 d x}{2}\right )-195 A \sin \left (5 c+\frac{7 d x}{2}\right )+304 A \sin \left (3 c+\frac{9 d x}{2}\right )+90 A \sin \left (4 c+\frac{9 d x}{2}\right )+214 A \sin \left (5 c+\frac{9 d x}{2}\right )+2094 B \sin \left (c-\frac{d x}{2}\right )-1314 B \sin \left (c+\frac{d x}{2}\right )+1650 B \sin \left (2 c+\frac{d x}{2}\right )+450 B \sin \left (c+\frac{3 d x}{2}\right )-1230 B \sin \left (2 c+\frac{3 d x}{2}\right )+1050 B \sin \left (3 c+\frac{3 d x}{2}\right )-1278 B \sin \left (c+\frac{5 d x}{2}\right )+90 B \sin \left (2 c+\frac{5 d x}{2}\right )-918 B \sin \left (3 c+\frac{5 d x}{2}\right )+450 B \sin \left (4 c+\frac{5 d x}{2}\right )-630 B \sin \left (2 c+\frac{7 d x}{2}\right )-60 B \sin \left (3 c+\frac{7 d x}{2}\right )-480 B \sin \left (4 c+\frac{7 d x}{2}\right )+90 B \sin \left (5 c+\frac{7 d x}{2}\right )-144 B \sin \left (3 c+\frac{9 d x}{2}\right )-30 B \sin \left (4 c+\frac{9 d x}{2}\right )-114 B \sin \left (5 c+\frac{9 d x}{2}\right )\right )}{480 a^3 d (\cos (c+d x)+1)^3} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.112, size = 334, normalized size = 1.7 \begin{align*} -{\frac{A}{20\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{5}}+{\frac{B}{20\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{5}}-{\frac{2\,A}{3\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{3}}+{\frac{B}{2\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) ^{3}}-{\frac{31\,A}{4\,d{a}^{3}}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) }+{\frac{17\,B}{4\,d{a}^{3}}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) }-{\frac{13\,A}{2\,d{a}^{3}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) }+3\,{\frac{\ln \left ( \tan \left ( 1/2\,dx+c/2 \right ) -1 \right ) B}{d{a}^{3}}}+{\frac{7\,A}{2\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-1}}-{\frac{B}{d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-1}}+{\frac{A}{2\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) ^{-2}}+{\frac{7\,A}{2\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-1}}-{\frac{B}{d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-1}}+{\frac{13\,A}{2\,d{a}^{3}}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) }-3\,{\frac{\ln \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) B}{d{a}^{3}}}-{\frac{A}{2\,d{a}^{3}} \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) ^{-2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.00176, size = 509, normalized size = 2.6 \begin{align*} -\frac{A{\left (\frac{60 \,{\left (\frac{5 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac{7 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}}\right )}}{a^{3} - \frac{2 \, a^{3} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac{a^{3} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}}} + \frac{\frac{465 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac{40 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac{3 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}}}{a^{3}} - \frac{390 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{a^{3}} + \frac{390 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{a^{3}}\right )} - 3 \, B{\left (\frac{40 \, \sin \left (d x + c\right )}{{\left (a^{3} - \frac{a^{3} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )}{\left (\cos \left (d x + c\right ) + 1\right )}} + \frac{\frac{85 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac{10 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac{\sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}}}{a^{3}} - \frac{60 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{a^{3}} + \frac{60 \, \log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{a^{3}}\right )}}{60 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.44425, size = 756, normalized size = 3.86 \begin{align*} \frac{15 \,{\left ({\left (13 \, A - 6 \, B\right )} \cos \left (d x + c\right )^{5} + 3 \,{\left (13 \, A - 6 \, B\right )} \cos \left (d x + c\right )^{4} + 3 \,{\left (13 \, A - 6 \, B\right )} \cos \left (d x + c\right )^{3} +{\left (13 \, A - 6 \, B\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \,{\left ({\left (13 \, A - 6 \, B\right )} \cos \left (d x + c\right )^{5} + 3 \,{\left (13 \, A - 6 \, B\right )} \cos \left (d x + c\right )^{4} + 3 \,{\left (13 \, A - 6 \, B\right )} \cos \left (d x + c\right )^{3} +{\left (13 \, A - 6 \, B\right )} \cos \left (d x + c\right )^{2}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \,{\left (16 \,{\left (19 \, A - 9 \, B\right )} \cos \left (d x + c\right )^{4} + 3 \,{\left (239 \, A - 114 \, B\right )} \cos \left (d x + c\right )^{3} +{\left (479 \, A - 234 \, B\right )} \cos \left (d x + c\right )^{2} + 15 \,{\left (3 \, A - 2 \, B\right )} \cos \left (d x + c\right ) - 15 \, A\right )} \sin \left (d x + c\right )}{60 \,{\left (a^{3} d \cos \left (d x + c\right )^{5} + 3 \, a^{3} d \cos \left (d x + c\right )^{4} + 3 \, a^{3} d \cos \left (d x + c\right )^{3} + a^{3} d \cos \left (d x + c\right )^{2}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.22871, size = 315, normalized size = 1.61 \begin{align*} \frac{\frac{30 \,{\left (13 \, A - 6 \, B\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right )}{a^{3}} - \frac{30 \,{\left (13 \, A - 6 \, B\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right )}{a^{3}} + \frac{60 \,{\left (7 \, A \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 2 \, B \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 5 \, A \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 2 \, B \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{2} a^{3}} - \frac{3 \, A a^{12} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 3 \, B a^{12} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 40 \, A a^{12} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 30 \, B a^{12} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 465 \, A a^{12} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 255 \, B a^{12} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{a^{15}}}{60 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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